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JEE Main & Advanced Sample Paper JEE Main Sample Paper-40

  • question_answer
    A current of 2.0A when passed for 5 hours through a molten metal salt deposits 22.2g of metal of atomic weight 177.The oxidation state of the metal in the metal salt is

    A) +1                              

    B) +2

    C) +3                              

    D) +4

    Correct Answer: C

    Solution :

    \[{{\text{E}}_{\text{metal}}}\] (Wt of metal x 96500)/No of coulombs\[=\frac{(22.2\times 96500)}{(2\times 5\times 60\times 60)}=59.5\] Oxidation no. of metal \[=\frac{177}{59.5}=+3\]


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