JEE Main & Advanced Sample Paper JEE Main Sample Paper-3

  • question_answer
    If the S.D. of a variable X is \[\sigma ,\] then the S.D. of \[\frac{aX+b}{c}\] (a, b, c are constant) is

    A)  \[\frac{a}{c}\sigma \]                   

    B)  \[\left| \frac{a}{c} \right|\sigma \]

    C)  \[\left| \frac{c}{a} \right|\sigma \]                        

    D)  \[\frac{c}{a}\sigma \]

    Correct Answer: B

    Solution :

     Let\[Y=\frac{aX+b}{c}\] Then\[\overline{Y}=\frac{1}{c}(a\overline{X}+b)\Rightarrow Y-\overline{Y}=\frac{a}{c}(X-\overline{Y})\] \[\Rightarrow \]\[\frac{1}{N}\sum {{(Y-\overline{Y})}^{2}}=\frac{{{a}^{2}}}{{{c}^{2}}}\frac{1}{N}\sum {{(X-\overline{X})}^{2}}\] There fore S.D. of Y \[=\sqrt{\frac{{{a}^{2}}}{{{c}^{2}}}\frac{1}{N}\sum {{(X-\overline{X})}^{2}}}=\sqrt{\frac{{{a}^{2}}}{{{c}^{2}}}\sigma }=\left| \frac{a}{c} \right|\sigma \]


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