A) \[6\times {{10}^{20}}\]
B) \[1.2\times {{10}^{21}}\]
C) \[3\times {{10}^{21}}\]
D) \[3.6\times {{10}^{21}}\]
Correct Answer: D
Solution :
No. of atoms of hydrogen in 0.046 g of alcohol \[\frac{0.046}{46}\times 6\times {{10}^{23}}\times 6\]\[=1\times {{10}^{-3}}\times 6\times {{10}^{23}}\times 6=3.6\times {{10}^{21}}\]
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