JEE Main & Advanced Sample Paper JEE Main Sample Paper-39

  • question_answer
    A beam of light of intensity 12 watt/cm2 is incident on a totally reflecting plane mirror of area 1.5 cm2, then the force (in newton) acting on the mirror will be

    A)  \[2.4\times {{10}^{-6}}\]               

    B)  \[1.2\times {{10}^{-7}}\]

    C)  \[3.6\times {{10}^{-8}}\]               

    D)  \[5.6\times {{10}^{-5}}\]

    Correct Answer: B

    Solution :

     Pressure of lighten totally reflecting surface \[P=\frac{2I}{C}\](C-velocity of light) \[P=\frac{F}{A}=\frac{2I}{C}\] \[\Rightarrow \] \[F=\frac{2IA}{C}=\frac{2\times 12\times 1.5\times {{10}^{-4}}}{{{10}^{-4}}\times 3\times {{10}^{8}}}\] \[=\frac{8\times 15\times {{10}^{-8}}}{10}=12\times {{10}^{-8}}=1.2\times {{10}^{-7}}N\]


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