A) \[{{r}^{2}}\]
B) 1/r
C) r
D) \[-1/{{r}^{2}}\]
Correct Answer: A
Solution :
Terminal velocity attained by falling object \[{{V}_{t}}=\frac{3{{r}^{2}}(d-\rho )g}{a\eta }\]thus, \[{{V}_{t}}\alpha {{r}^{2}}\]
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