question_answer

In the case of a charged metallic sphere, potential (V) changes with respect to distance (S) from the centre as

A)  A                                

B)  B

C)  C                               

D)  D                          

Correct Answer: B

Solution :

 In the charged metallic sphere potential is given by \[V=\left\{ \begin{matrix}    \frac{1}{4\pi {{\varepsilon }_{0}}}\frac{q}{R}\text{where}\,r\le R  \\    \frac{1}{4\pi {{\varepsilon }_{0}}}\frac{q}{R}\text{where}\,r>R  \\ \end{matrix} \right.\] So graph is