A) 300 K
B) 400 K
C) 500 K
D) 700 K
Correct Answer: A
Solution :
\[\eta =\left( 1-\frac{{{T}_{c}}}{{{T}_{H}}} \right)\times 100\]\[\Rightarrow \]\[70=\left( 1-\frac{{{T}_{c}}}{1000} \right)\times 100\]\[0.7=1-\frac{{{T}_{c}}}{1000}\]\[\therefore \]\[\frac{{{T}_{c}}}{1000}=0.3\]or\[{{T}_{c}}=300K.\]
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