A) \[\sqrt{\frac{2Tg}{\pi d}}\]
B) \[\sqrt{\frac{2\pi T}{dg}}\]
C) \[\sqrt{\frac{2T}{\pi dg}}\]
D) any length
Correct Answer: D
Solution :
\[mg=2TL\Rightarrow \pi {{r}^{2}}Ldg=2TL\Rightarrow \pi {{r}^{2}}dg=2T.\] This relation is independent of L.
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