A) log K vs T will give a straight line
B) log K vs 1/T gives a straight line with a slope \[-2500/2.303\text{ }R\]
C) half life of reaction will be more at higher temperature
D) log K vs 1 /T gives a straight line with a slope 2500/R
Correct Answer: B
Solution :
log\[\log K=\log A-\frac{{{E}_{a}}}{2.303R}\frac{1}{T}\] (Arrhenius equation) Plot of log K Vs 1/T gives a straight line with slope \[-{{E}_{a}}/2.303R\]
You need to login to perform this action.
You will be redirected in
3 sec
