A) \[10.376\]
B) \[5.19\]
C) \[7.289\]
D) \[2.144\]
Correct Answer: B
Solution :
For bcc lattice, number of atoms per unit cell = 2 Now \[d=\frac{n\times M}{{{a}^{3}}\times {{N}_{0}}}=\frac{2\times 100}{{{(4\times {{10}^{-8}}cm)}^{3}}\times 6.02\times {{10}^{23}}}\]\[=200/38.528=5.19g/cc\]
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