JEE Main & Advanced Sample Paper JEE Main Sample Paper-35

  • question_answer
    For the cell, \[Hg\left| H{{g}_{2}}C{{l}_{2}} \right|C{{l}^{-}}(0.1\,M)||\,C{{l}^{-}}(0.01\,M)\]\[\left| C{{l}_{2}},Pt\,{{E}^{o}}_{cell}=1.10\,V \right.\], Hence \[{{E}_{cell}}\] is

    A)  \[1.1591\] V                      

    B)  \[-1.1591\] V

    C)  \[1.0409\] V                      

    D)  \[-1.0409\] V

    Correct Answer: A

    Solution :

    \[{{E}_{cell}}\] is calculated from nemxt equation.


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