JEE Main & Advanced Sample Paper JEE Main Sample Paper-35

  • question_answer
    In hydrogen atom, electron moves in an orbit of radius \[0.5\,\overset{0}{\mathop{A}}\,\] making \[{{10}^{16}}\] revolutions per second. The magnetic moment associated with orbital motion of the electron is :

    A)  \[0.88\times {{10}^{-23}}A{{m}^{2}}\]  

    B)  \[1.26\times {{10}^{-23}}A{{m}^{2}}\]

    C)  \[1.75\times {{10}^{-23}}A{{m}^{2}}\] 

    D)  \[2.2\times {{10}^{-23}}A{{m}^{2}}\]

    Correct Answer: B

    Solution :

    Magnetic moment \[=iA=(qf)\,(\pi {{r}^{2}})\] \[=1.26\,\times {{10}^{-23}}\,A{{m}^{2}}\] (by substituting the values)


You need to login to perform this action.
You will be redirected in 3 sec spinner