question_answer

The following equilibrium are given,

\[{{N}_{2}}+3{{H}_{2}}2N{{H}_{3}}.....{{K}_{1}}\]

\[{{N}_{2}}+{{O}_{2}}2NO.....{{K}_{2}}\]

\[{{H}_{2}}+\frac{1}{2}{{O}_{2}}\frac{5}{2}{{O}_{2}}.......{{K}_{3}}\]

The equilibrium constant of the reaction\[2N{{H}_{3}}+\frac{5}{2}{{O}_{2}}2NO+3{{H}_{2}}O\] in term of \[{{K}_{1}}\]  \[{{K}_{2}}\] and \[{{K}_{3}}\] is

A)  \[\frac{{{K}_{1}}{{K}_{2}}}{{{K}_{3}}}\]                 

B)  \[\frac{{{K}_{1}}K_{3}^{2}}{{{K}_{2}}}\]

C)  \[\frac{{{K}_{2}}K_{3}^{3}}{{{K}_{1}}}\]                

D)  \[{{K}_{1}}{{K}_{2}}{{K}_{3}}\]

Correct Answer: C

Solution :

To getting equation We have to do, reverse of equation 1st + equation 2nd +  Equation 3rd, we get