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JEE Main & Advanced Sample Paper JEE Main Sample Paper-34

  • question_answer
    Lissajou's figure obtained by the two waves with same frequency but different amplitude and phase difference of \[\pi /2\], will be in the form of:

    A)  straight line                      

    B)  circle

    C)  ellipse                 

    D)  figure of 8

    Correct Answer: C

    Solution :

    \[x=A\sin \omega t\]             \[{{x}^{'}}=B\,\sin (wt\,+\pi /2)\,=B\cos \omega t\]             \[{{\sin }^{2}}\omega t\,+{{\cos }^{2}}\omega t\,=\frac{{{x}^{2}}}{{{A}^{2}}}\,+\frac{{{x}^{'2}}}{{{B}^{2}}}=1\]             hence ellipse.


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