JEE Main & Advanced Sample Paper JEE Main Sample Paper-34

  • question_answer
    A soap bubble (surface tension 30 dyne/cm) has radius of 1 cm. The work done in doubling its radius would be:

    A)  30 erg                  

    B)  11.35 erg

    C)  2261 erg             

    D)  96 erg

    Correct Answer: C

    Solution :

    \[W=2T\times 4\pi \,\,\left[ {{(2r)}^{2}}-{{r}^{2}} \right]=24\,\times T\times \pi {{r}^{2}}\] \[=24\,\times 30\,\times 3.14\,\times {{1}^{2}}\,=2260.8\,erg\] Ans.


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