JEE Main & Advanced Sample Paper JEE Main Sample Paper-34

  • question_answer
    Normal is drawn to the ellipse \[\frac{{{x}^{2}}}{27}+{{y}^{2}}=1\] at a point \[\left( 3\sqrt{3}cos\theta ,\sin \theta  \right)\]where \[0<\theta <\frac{\pi }{2}\]. The value of \[\theta \] such that the area of triangle formed by normal and coordinate axes is maximum, is

    A)  \[\frac{\pi }{8}\]                             

    B)  \[\frac{\pi }{6}\]

    C)  \[\frac{\pi }{4}\]                                             

    D)  \[\frac{\pi }{3}\]

    Correct Answer: C

    Solution :

    \[\theta \,=\frac{\pi }{4}.\]


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