A) \[\frac{1}{8}\]
B) \[\frac{1}{4}\]
C) \[\frac{1}{16}\]
D) \[\frac{1}{32}\]
Correct Answer: A
Solution :
Like radioactivity \[N={{N}_{0}}\,{{\left( \frac{1}{2} \right)}^{{{t}_{1/2}}}}\] We can use \[A={{A}_{0}}\,{{\left( \frac{1}{2} \right)}^{\frac{t}{{{t}_{1/2}}}}}\] \[{{t}_{1/2}}\] is time in which amplitude is reduced to half of its initial value. In this case it is 2 Now \[A={{A}_{0}}\,{{\left( \frac{1}{2} \right)}^{\frac{2+4}{2}}}=\frac{1}{8}\,{{A}_{0}}\]j
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