JEE Main & Advanced Sample Paper JEE Main Sample Paper-32

  • question_answer
    A \[5.0\text{ }c{{m}^{3}}\] solution of \[{{H}_{2}}{{O}_{2}}\] liberates 0.508 g of \[{{1}_{2}}\], from an acidified KI solution. The strength of \[{{H}_{2}}{{O}_{2}}\], solution in terms of volume strength at STP is:

    A) 2.24V            

    B)    1.12V

    C) 4.48V      

    D)                   8.96V

    Correct Answer: C

    Solution :

    \[meq\,{{H}_{2}}{{O}_{2}}\,=meq\,{{I}_{2}}\]                 \[N\times 5=\frac{0.508\times 2}{254}\,\times 1000\] or Normality = 0.8N                 Volume strength                 \[=5.6\,\times N=5\,.6\,\times 8=4.48\,V\].     


You need to login to perform this action.
You will be redirected in 3 sec spinner