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JEE Main & Advanced Sample Paper JEE Main Sample Paper-32

  • question_answer
    The time period of a simple pendulum is 2 sec. Initial amplitude is 10 degree becomes 5degree in 100 oscillations .The quality factor of the weakly damped oscillation will be:

    A) \[\pi 200/In\,2\]     

    B)   \[\pi 100/In\,2\]

    C) \[\pi 300/In\,2\]

    D) None

    Correct Answer: B

    Solution :

    \[A'=A\,{{e}^{-bt}}\]                 \[5=10\,{{e}^{-b100\times 2}}\] \[b=\ln 2/200\] \[Q={{\omega }_{0}}\,/2b=2\pi /T2b\]


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