question_answer

A block of mass 0.1 kg is held against a wall applying a horizontal force of 5N on the block. If the coefficient of friction between the block and the wall is 0.50, the magnitude of frictional force acting on the block is:

A) 2.5 N          

B)                    4.9N

C) 0.49 N           

D)    0.98 N

Correct Answer: D

Solution :

\[N=5(N)\]                 \[{{F}_{\max }}=0.5\times 5=2.5\,N\] Vertical equilibrium of block is maintained if, \[f=mg=0.98(N)<{{(f)}_{\max }}\]