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  3. JEE Main & Advanced

JEE Main & Advanced Sample Paper JEE Main Sample Paper-31

  • question_answer
    Let f: (-1,1) ?> R be a differentiable function with \[f(0)=-1\] and \[f'(0)=1\]. Let \[{{\left( f(2fx)+2) \right)}^{2}}\], then \[g'(0)\] equals

    A) \[-4\]

    B) 0

    C) \[-2\]

    D) 4

    Correct Answer: A

    Solution :

    \[g'(x)=2f(2f(x)+2)\times f'(2f(x)+2)\times 2f'(x)\]                 Put\[x=0,\] we get \[g'(0)=2(-1)\times 1\times 2\times 1=-4\]          


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