A) \[\sqrt{\frac{k}{b}}\]
B) \[\sqrt{\frac{b}{k}}\]
C) \[\sqrt{\frac{a}{k}}\]
D) \[\sqrt{\frac{k}{a}}\]
Correct Answer: D
Solution :
\[a{{x}^{2}}+b{{v}^{2}}=k\] \[b{{v}^{2}}=k-a{{x}^{2}}\] \[{{v}^{2}}=\frac{k}{b}-\frac{a}{b}{{x}^{2}}\] Compare with\[{{v}^{2}}={{A}^{2}}{{\omega }^{2}}-{{\omega }^{2}}{{x}^{2}}\] \[{{\omega }^{2}}=a/b\] and \[{{A}^{2}}{{\omega }^{2}}=k/b\] \[A=\sqrt{\frac{{{A}^{2}}{{\omega }^{2}}}{{{\omega }^{2}}}}=\sqrt{\frac{k/{{b}^{2}}}{a/b}}=\sqrt{\frac{k}{a}}\]
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