question_answer

Compound (A) \[({{C}_{4}}{{H}_{8}}{{O}_{3}})\] reacts with \[NaHC{{O}_{3}}\] and evolves \[C{{O}_{2}}(g)\]. (A) reacts with \[LiA1{{H}_{4}}\] to give a compound (B) which is achiral. The structure of is:

A)            

B)    

C)             

D)   

Correct Answer: A

Solution :

\[NaHC{{O}_{3}}\]test shows the presence of the (-COOH) group, and from the structures given in the problem, only the compound in (A) on reduction with \[LiAl{{H}_{4}}\] gives a chiral product. The compounds (2), (3) and (4) with \[LiAl\,{{H}_{4}}\] will give chiral products. So the answer is (1)