JEE Main & Advanced Sample Paper JEE Main Sample Paper-30

  • question_answer
    Ideal gas 'A' is given by internal energy of\[U=2{{P}_{0}}{{V}_{0}}\]. If gas undergoes an expansion, as shown below, then heat absorbed in the process will be (\[{{P}_{0}}=\] external pressure)

    A)  \[{{P}_{0}}{{V}_{0}}\]          

    B) \[\frac{{{P}_{0}}{{V}_{0}}}{2}\]

    C) \[3{{P}_{0}}{{V}_{0}}\]                            

    D) \[\frac{3}{2}{{P}_{0}}{{V}_{0}}\]

    Correct Answer: A

    Solution :

    According to first law of thermodynamics \[du=dq-dw\] \[dw=-\int{{{P}_{ext}}\cdot dv=-{{P}_{0}}{{V}_{0}}}\] \[\therefore dq=2{{P}_{0}}{{V}_{0}}-{{P}_{0}}{{V}_{0}}\] \[dq={{P}_{0}}{{V}_{0}}\] Heat absorbed in the process will be\[{{P}_{0}}{{V}_{0}}\].                    


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