A) \[0,J16J\]
B) \[16J,-16J\]
C) \[0J,-16J\]
D) \[-16J,-16J\]
Correct Answer: C
Solution :
On ground \[{{W}_{f}}\] because \[S=0\] on block: \[{{W}_{N}}+{{W}_{g}}+{{W}_{f}}=\Delta \,KE\] \[0+0+{{W}_{f}}=0-\frac{1}{2}\times 2\times {{4}^{2}}=16J\]
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