A) 1000 J
B) 600 J
C) 1250 J
D) zero
Correct Answer: A
Solution :
Source \[emf\,e=2{{t}^{2}}-4t=0\] i.e., at \[t=0\] and \[t=2\,\sec \] For inductor, \[L\frac{di}{dt}=e\] \[\int_{{}}^{{}}{di=\int_{{}}^{{}}{\frac{e}{L}dt=\int\limits_{0}^{t}{\frac{(2{{t}^{2}}-4t)}{L}dt}}}\] \[i=\frac{\left( \frac{2{{t}^{3}}}{3}-2{{t}^{2}} \right)}{L}\] At \[t=2,\,i=-750\,A\] Energy stored, \[U=\frac{1}{2}L{{i}^{2}}=1000J\]
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