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JEE Main & Advanced Sample Paper JEE Main Sample Paper-2

  • question_answer
    Solubility product of \[{{A}_{2}}B\] is \[4\times {{10}^{-9}}\ {{\text{(mol/lit}\text{.)}}^{3}}\]. Its solubility is

    A)  \[{{10}^{-3}}M\]                             

    B)  \[{{10}^{-4}}M\]

    C)  \[{{4}^{1/3}}\times {{10}^{-3}}M\]                         

    D)  \[2\times {{10}^{-5}}M\]

    Correct Answer: A

    Solution :

    \[{{A}_{2}}B\,2{{\underset{2S}{\mathop{A}}\,}^{+}}+B_{S}^{2-}\] \[{{(2S)}^{2}}S=4\times {{10}^{-9}}\] \[\Rightarrow \,\,S={{10}^{-3}}\] moles/It.


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