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  3. JEE Main & Advanced

JEE Main & Advanced Sample Paper JEE Main Sample Paper-2

  • question_answer
    The number of moles of iron metal produced by passage of 4.00 A of current for 1.00 hour through \[FeS{{O}_{4}}\] solution is (Assume current efficiency to be 60%)

    A)  0.0447                 

    B)  0.513

    C)  0.825                   

    D)  0.0003

    Correct Answer: A

    Solution :

    \[\frac{w}{M}=\frac{It\times x}{96500n}=\frac{4\times 3600\times 0.6}{96500\times 2}=0.0447\]


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