JEE Main & Advanced Sample Paper JEE Main Sample Paper-2

  • question_answer
    In a saturated solution of sparingly soluble strong electrolyte \[AgI{{O}_{3}}\] (Molecular mass = 283), the equilibrium which sets in is\[AgI{{O}_{3}}(s)\,A{{g}^{+}}(aq.)+lO_{3}^{-}(aq.)\]. If the solubility product constant \[{{k}_{sp}}\] of \[AgI{{O}_{3}}\] at a given temperature is \[1.0\times {{10}^{-8}},\] what is the mass of \[AgI{{O}_{3}}\] contained in 100 ml of its saturated solution?

    A)  \[28.3\times {{10}^{-2}}g\]                        

    B)  \[2.83\times {{10}^{-3}}g\]

    C)  \[1.0\times {{10}^{-7}}g\]           

    D)         \[1.0\times {{10}^{-4}}g\]

    Correct Answer: B

    Solution :

    \[AgI{{O}_{3}}(s)\,A{{g}^{+}}(aq.)+IO_{3}^{-}(aq.)\] Let solubility of \[AgI{{O}_{3}}\] be S. \[{{K}_{sp}}=[A{{g}^{+}}][IO_{3}^{-}]\] \[1.0\times {{10}^{-8}}={{S}^{2}}\] In 1000 ml, of \[AgI{{O}_{3}}\] dissolved \[=1\times {{10}^{-4}}\] In 100 ml, mol of \[AgI{{O}_{3}}\] dissolved \[=1\times {{10}^{-5}}\] Mass of \[AgI{{O}_{3}}\] in \[100\,ml=1\times {{10}^{-5}}\times 283\] \[=2.83\times {{10}^{-3}}\]


You need to login to perform this action.
You will be redirected in 3 sec spinner