JEE Main & Advanced Sample Paper JEE Main Sample Paper-2

  • question_answer
    Molar conductance of a 1.5 M solution of an electrolyte is found to be 138.9 S cm2. The specific conductance of this solution is

    A)  \[0.208\,S\,c{{m}^{-1}}\]                            

    B)  \[0.102\,\,S\,c{{m}^{-1}}\]

    C)  \[0.320\,S\,c{{m}^{-1}}\]                            

    D)  \[0.152\,S\,c{{m}^{-1}}\]

    Correct Answer: A

    Solution :

    Molar conductance \[=\frac{k\times 1000}{M}\] \[138.9=\frac{k\times 1000}{1.5}\] or \[k=0.208\,Sc{{m}^{-1}}\]


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