A) \[{{N}_{2}}^{+}<{{N}_{2}}\] and \[N{{O}^{+}}<NO\]
B) \[{{N}_{2}}^{+}<{{N}_{2}}\] and \[NO<N{{O}^{+}}\]
C) \[{{N}_{2}}<{{N}_{2}}^{+}\] and \[N{{O}^{+}}<NO\]
D) \[{{N}_{2}}<{{N}_{2}}^{+}\] and \[NO<N{{O}^{+}}\]
Correct Answer: B
Solution :
\[P(3\le r\le 8)=1-P(0)+P(1)+P(2)+P(9)+P(10)]\] \[=1-\frac{1}{{{2}^{10}}}\,{{[}^{10}}{{C}_{0}}{{+}^{10}}{{C}_{1}}{{+}^{10}}{{C}_{2}}{{+}^{10}}{{C}_{9}}\,{{+}^{10}}{{C}_{10}}]\] \[=1-\frac{1}{{{2}^{10}}}\,[2+20+45]\] \[=1-\frac{67}{1024}\,=\frac{1024-67}{1024}\,=\frac{957}{1024}\]
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