A) \[-98.1\times {{10}^{2}}kJ\]
B) \[-9.8\,kJ\]
C) \[-39.2\,J\]
D) \[-4.9\,kJ\]
Correct Answer: B
Solution :
\[\therefore \] \[{{\ell }_{1}}=\underset{x\to 0}{\mathop{Lim}}\,\,\,\frac{({{a}^{\sin x}}-1)\,\sin x}{(1+x-\cos x)\sin x}\] \[=\underset{x\to 0}{\mathop{Lim}}\,\,\,\frac{({{a}^{\sin x}}-1)\,}{\sin x(1+x-\cos x)}\,.\frac{(\sin x)}{x}.x\] pascal \[=(\ell n\,a)\,\underset{x\to 0}{\mathop{Lim}}\,\,\frac{x}{(1+x-\cos x)}\] = - 9.8 kJ
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