question_answer

The state of hybridization of 'B' atom is Borax \[(N{{a}_{2}}{{B}_{4}}{{O}_{7}}\,.\,10{{H}_{2}}O)\] is

A)  All \[s{{p}^{2}}\] hybridised

B)  Three \[s{{p}^{2}}\] and one \[s{{p}^{3}}\] hybridised

C)  One \[s{{p}^{2}}\] and three \[s{{p}^{3}}\] hybridised

D)  Two \[s{{p}^{2}}\] and two \[s{{p}^{3}}\] hybridized

Correct Answer: D

Solution :

Borax \[(N{{a}_{2}}{{B}_{4}}{{O}_{7}}.10\,\,{{H}_{2}}O)\]is actually made from two tetrahedral and two triangular units joined as shown in figure and should be written as\[N{{a}_{2}}({{B}_{4}}{{O}_{5}}{{(OH)}_{4}}.8{{H}_{2}}O)\].