A) \[1.5\,L\]
B) \[0.5\,L\]
C) \[1.95\,L\]
D) \[2\,L\]
Correct Answer: A
Solution :
Meq. before dilution = meq. after dilution \[{{N}_{1}}{{V}_{1}}={{N}_{2}}{{V}_{2}}\] \[8\times V=\frac{7.3}{36.5}\times \frac{1000}{100}\times 2\] \[V=\frac{4}{8}.5L\] So volume of water added 1.5LYou need to login to perform this action.
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