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JEE Main & Advanced Sample Paper JEE Main Sample Paper-28

  • question_answer
    \[1.44\,g\] of titanium (Ti) reacts with excess of \[{{O}_{2}}\] and produced \[x\] g of a non-stoichiometric compound. \[T{{i}_{1.44}}O\]. The value x is (Atomic mass of \[Ti=48\,u\])

    A)  \[1.44\]

    B)  \[1.77\]

    C)  \[1.33\]                              

    D)  \[1.55\]

    Correct Answer: B

    Solution :

    In the reaction \[Ti+{{O}_{2}}\xrightarrow{{}}T{{i}_{1.44}}O\] on applying POAC for Ti-atom, \[\therefore \]Number of moles of Titanium\[=1.44\times \]Number of moles of \[T{{i}_{1.44}}O\] \[\frac{1.44}{48}=\frac{1.44x}{48\times 1.44+16}\] \[x=1.77g\]


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