A) total average energy in one loop is constant.
B) total average energy in halfloop( between node and antinode) is constant.
C) total average energy in any section of loop is constant.
D) potential energy in any section of loop is proportional to square of slope of that section of string.
Correct Answer: C
Solution :
Total energy on loop is \[\frac{\lambda }{8}\mu {{\omega }^{2}}{{A}^{2}}\] which is constant. Also constant in half loop but not constant in any section, potential is proportional to square of slope. We have to choose incorrect.
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