A) \[\frac{\pi \ell n2}{8}\]
B) \[\frac{\pi \ell n2}{4}\]
C) \[\frac{\pi \ell n2}{32}\]
D) \[\frac{\pi \ell n2}{16}\]
Correct Answer: D
Solution :
Put \[2x=\tan \theta ;\] \[I=\frac{1}{2}\,\int\limits_{0}^{\pi /4}{\ell n(1+\tan \theta )\,d\theta }\] \[\therefore \,\,I=\frac{\pi }{16}\,\ln \,2\] (using king property)
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