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  3. JEE Main & Advanced

JEE Main & Advanced Sample Paper JEE Main Sample Paper-27

  • question_answer
    A number x is chosen at random from the set {1,2, 3,4,.....,100}. Define the event A = the chosen number \[x\] satisfies, \[\frac{(x-10)(x-50)}{(x-30)}\ge 0\]. Then P is equal to

    A)  \[0.20\]                        

    B)  \[0.70\]

    C)  \[0.71\]                                    

    D)  \[0.51\]  

    Correct Answer: C

    Solution :

    Probability \[=\frac{71}{100}=0.71\]


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