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JEE Main & Advanced Sample Paper JEE Main Sample Paper-27

  • question_answer
    The general solution of differential equation,\[\sin 2x.\,\left( \frac{dy}{dx}-\sqrt{\tan x} \right)-y=0\], is

    A)  \[y\sqrt{\cot x}=\tan x+C\]       

    B)  \[y\sqrt{\cot x}=x+C\]

    C)  \[y\sqrt{\tan x}=\cot x+C\]       

    D)  \[y\sqrt{\tan x}=x+C\][Note: C denotes constant of integration]

    Correct Answer: B

    Solution :

    \[\frac{dy}{dx}+\left( \frac{-1}{\sin 2x} \right)y=\sqrt{\tan x}\] (Linear differential equation) \[\therefore \] General solution is, \[y\sqrt{\cot \,x}=x+C\]


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