A) 50 W
B) \[86.6\] W
C) 100 W
D) 200 W
Correct Answer: B
Solution :
Average power dissipated in an AC circuit, \[{{P}_{av}}={{V}_{rms}}\,{{I}_{rms}}\,\cos \phi \] ?(i) Where, the term \[\cos \phi \] is known as power factor Given \[{{V}_{rms}}=100\,V,\,\,R=100\Omega ,\,\phi =\,{{30}^{0}}\] \[\therefore \,\,{{I}_{rms}}\,=\frac{{{V}_{rms}}}{R}=\frac{100}{100}=1A\] Putting the values in eq. (i) we get \[{{P}_{av}}\,=100\times 1\,\times \,\cos {{30}^{0}}\] \[=100\frac{\sqrt{3}}{2}\] \[=50\,\sqrt{3}\,=86.6\,w\]You need to login to perform this action.
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