A) \[\frac{10}{e}C\]
B) \[\frac{e}{10}C\]
C) \[\frac{10}{{{e}^{2}}}C\]
D) \[\frac{{{e}^{2}}}{10}C\]
Correct Answer: A
Solution :
Final charge on capacitor is given by \[q={{q}_{0}}{{e}^{-t/RC}}\] where, \[{{q}_{0}}=\] charge on capacitor at t = 0and RC = time constant of the circuit Putting \[{{q}_{0}}=C{{V}_{0}}\]\[q=C{{V}_{0}}{{e}^{-t/RC}}\] Given: \[C=2,\,\,{{V}_{0}}=5V,\,\,R=6\Omega \] and \[t=12\,s\] Hence, \[q=(2\times 5)\,{{e}^{-(12/6\times 2)}}\] \[=10{{e}^{-1}}\,=\frac{10}{e}C\]
You need to login to perform this action.
You will be redirected in
3 sec
