A) \[{{x}^{2}}=\pm 1\]
B) \[y=\pm 2\]
C) \[y=\pm \sqrt{2}\]
D) \[x=-1\pm \sqrt{2}\]
Correct Answer: C
Solution :
\[{{(x+1)}^{2}}-{{y}^{2}}=-4\Rightarrow \,\frac{{{y}^{2}}}{4}\,-\frac{{{(x+1)}^{2}}}{4}=1\] \[\therefore \,\,e=\sqrt{2}\] and directrix is \[y=\pm \,\frac{b}{e}\]
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