A) \[\ell \,n(\pi )\]
B) \[\ell \,n(2+\pi )\]
C) \[\ell \,n(1+\pi )\]
D) \[\ell \,n(2\pi )\]
Correct Answer: B
Solution :
\[\int\limits_{0}^{y}{{{e}^{y}}dy=\int\limits_{0}^{x}{(2+\cos x)\,dx\Rightarrow \,{{e}^{y}}-1=2x+\sin x}}\] For \[x=\frac{\pi }{2},\] we find \[y=\ell \,n\,(2+\pi )\]
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