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JEE Main & Advanced Sample Paper JEE Main Sample Paper-24

  • question_answer
    If for the equilibrium: \[N{{H}_{2}}COON{{H}_{4}}(s)\overset{{}}{leftrightarrows}\]          \[{{N}_{2}}(g)+3{{H}_{2}}(g)+CO(g)+\frac{1}{2}{{O}_{2}}(g)\]the value of Kp at 800 K is \[27\times {{2}^{\lambda /2}}\] and the equilibrium pressure is 22 atm value of \[\lambda \] is:

    A)  12                               

    B)  21

    C)  10                               

    D)  11

    Correct Answer: B

    Solution :

    \[N{{H}_{2}}COON{{H}_{4}}(s)\rightleftharpoons \] \[{{N}_{2}}(g)\,+3{{H}_{2}}(g)\,+CO(g)\,+\frac{1}{2}\,{{O}_{2}}(g)\] \[p\,\,\,\,\,\,\,\,\,\,\,\,\,3p\,\,\,\,\,\,\,\,\,\,\,p\,\,\,\,\,\,\,\,\,\,\,\,\,\,\frac{p}{2}\] Total pressure at equilibrium = 2 atm            \[p+3p+p+\frac{p}{2}\,=22\] \[\Rightarrow \,\frac{11}{2}\,p=22\,\,\,\Rightarrow \,p=4\,\,atm\] \[Kp=p\,{{(3p)}^{3}}p\sqrt{\frac{p}{2}}\] \[\Rightarrow \,27\times {{2}^{\lambda /2}}\,=27{{(4)}^{11/2}}\,{{2}^{-1/2}}\] \[\Rightarrow \,\,{{2}^{\lambda /2}}\,={{2}^{21/2}}\]\[\lambda =21\]


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