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JEE Main & Advanced Sample Paper JEE Main Sample Paper-24

  • question_answer
    1 g sample of alkaline earth metal react completely with \[4.08\,g{{H}_{2}}S{{O}_{4}}\] and yield an ionic product \[MS{{O}_{4}}\]. Then find out the atomic mass of Alkaline earth metal (M)?

    A)  9                                

    B)  24

    C)  40                               

    D)  87

    Correct Answer: B

    Solution :

    \[M+{{H}_{2}}S{{O}_{4}}\xrightarrow{\,}\,MS{{O}_{4}}+{{H}_{2}}\] \[\frac{mole\,of\,M}{1}\,=\frac{Mole\,of\,{{H}_{2}}S{{O}_{4}}}{1}\] \[\frac{1}{a}\,=\frac{4.08}{98}\] \[a=\frac{98}{4.08}=24.01\] This is atomic weight of M (M) = 24.


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