2. Sample Papers
  3. JEE Main & Advanced

JEE Main & Advanced Sample Paper JEE Main Sample Paper-24

  • question_answer
    Electrode potential for Zn electrode varies according to the equation.   \[{{E}_{z{{n}^{2+}}\left| Zn \right.}}=E_{Z{{n}^{2+}}\left| Zn \right.}^{o}-\frac{0.059}{2}\log \frac{1}{[Z{{n}^{2+}}]}\]. The graph of \[{{E}_{Z{{n}^{2+}}\left| zn \right.}}vs\log [Z{{n}^{2+}}]\]

    A)         

    B)      

    C)          

    D)       

    Correct Answer: B

    Solution :

    \[{{E}_{Z{{n}^{2+}}|Zn}}\,=E_{Z{{n}^{2+}}|Zn}^{o}\,-\frac{0.059}{2}\,\log \,[Z{{n}^{+2}}]\]Comparing with \[y=mx+c,\] graph between \[{{E}_{z{{n}^{2+}}|Zn}}\] and \[\log [Z{{n}^{2+}}]\] is a straight line with positive slope and positive intercept.


You need to login to perform this action.
You will be redirected in 3 sec spinner