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JEE Main & Advanced Sample Paper JEE Main Sample Paper-24

  • question_answer
    In a coil when current changes from 10A to 2A in time \[0.1\] s induced emf is \[3.28\] V. What is self-inductance of coil?

    A)  4H                              

    B)  \[0.4\] H

    C)  \[0.04\]H                                 

    D)  5H

    Correct Answer: C

    Solution :

    The induced emf is \[e=-L\,\frac{di}{dt}\] Here \[di=(2-10)A=-8A,\,\,dt=0.1\,s\] and \[e=3.28\,V\] \[\therefore \,\,3.28\,=-\frac{L(-8)}{0.1}\] \[\Rightarrow \,L=-\frac{3.28\,\times 0.1}{8}=0.04H\]


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