A) \[0.5\,A{{s}^{-1}}\]
B) \[2.0\,A{{s}^{-1}}\]
C) \[2.5\,A{{s}^{-1}}\]
D) \[0.25\,A{{s}^{-1}}\]
Correct Answer: C
Solution :
\[i={{i}_{0}}(1-{{e}^{-Rt/L}})\]\[\Rightarrow \,\frac{di}{dt}\,=0+\frac{{{i}_{0}}R}{L}{{e}^{-Rt/L}}\] initially t=0 \[\frac{di}{dt}\,=\frac{{{i}_{0}}\times R}{L}=\frac{E}{L}\,=\frac{5}{2}\,=2.5\,\,A{{s}^{-1}}\]
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