JEE Main & Advanced Sample Paper JEE Main Sample Paper-24

  • question_answer
    The electric field of a plane electromagnetic wave varies    with    time    of    amplitude \[2\,V{{m}^{-1}}\] propagating along Z-axis. The average energy density of the magnetic field is (in \[J{{m}^{-3}}\])

    A)  \[13.29\times {{10}^{-12}}\]               

    B)  \[8.85\times {{10}^{-12}}\]

    C)  \[17.72\times {{10}^{-12}}\]               

    D)  \[4.43\times {{10}^{-12}}\]

    Correct Answer: B

    Solution :

    Average energy density of magnetic field U is equal to Average energy density of electric field \[=\frac{1}{2}\,\times \frac{1}{2}\,{{\varepsilon }_{0}}{{E}^{2}}\] \[=\frac{1}{2}\,\times \frac{1}{2}\,\times 8.85\,\times {{10}^{-12}}\,\times {{(2)}^{2}}\] \[=8.85\,\times {{10}^{-12}}\]


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