A) \[+3.4\,\,eV\]
B) \[+1.51\,\,eV\]
C) \[-3.4\,eV\]
D) \[-1.51\,eV\]
Correct Answer: B
Solution :
We know that, \[{{E}_{m}}=\frac{13.6}{{{(n)}^{2}}}\] \[{{E}_{m}}=-\frac{13.6}{{{(3)}^{2}}}=-1.51\] Minimum energy required by electron in M shell = final energy at infinite- energy at M shell = 0 -(-1.51)=+1.51 eV which is transferred by second colliding electron.
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